x21x232设ⅹ=tanθ,则dⅹ=sec2θdθ.∴∫[x2/(1+x2)^(3/2)]dⅹ=∫(tan2θ/sec3θ)·sec2θdθ=∫(sin2θcosθ)dθ=∫sin2θd(sinθ)=(1/3)sin3θ+C=(1/3)·[x/√(1+x2)]3+C。2,x123带步骤解方程(x-
x21x232设ⅹ=tanθ,则dⅹ=sec2θdθ.∴∫[x2/(1+x2)^(3/2)]dⅹ=∫(tan2θ/sec3θ)·sec2θdθ=∫(sin2θcosθ)dθ=∫sin2θd(sinθ)=(1/3)sin3θ+C=(1/3)·[x/√(1+x2)]3+C。2,x123带步骤解方程(x-
x21x232设ⅹ=tanθ,则dⅹ=sec2θdθ.∴∫[x2/(1+x2)^(3/2)]dⅹ=∫(tan2θ/sec3θ)·sec2θdθ=∫(sin2θcosθ)dθ=∫sin2θd(sinθ)=(1/3)sin3θ+C=(1/3)·[x/√(1+x2)]3+C。2,x123带步骤解方程(x-
x21x232设ⅹ=tanθ,则dⅹ=sec2θdθ.∴∫[x2/(1+x2)^(3/2)]dⅹ=∫(tan2θ/sec3θ)·sec2θdθ=∫(sin2θcosθ)dθ=∫sin2θd(sinθ)=(1/3)sin3θ+C=(1/3)·[x/√(1+x2)]3+C。2,x123带步骤解方程(x-
x21x232设ⅹ=tanθ,则dⅹ=sec2θdθ.∴∫[x2/(1+x2)^(3/2)]dⅹ=∫(tan2θ/sec3θ)·sec2θdθ=∫(sin2θcosθ)dθ=∫sin2θd(sinθ)=(1/3)sin3θ+C=(1/3)·[x/√(1+x2)]3+C。2,x123带步骤解方程(x-
x21x232设ⅹ=tanθ,则dⅹ=sec2θdθ.∴∫[x2/(1+x2)^(3/2)]dⅹ=∫(tan2θ/sec3θ)·sec2θdθ=∫(sin2θcosθ)dθ=∫sin2θd(sinθ)=(1/3)sin3θ+C=(1/3)·[x/√(1+x2)]3+C。2,x123带步骤解方程(x-
x21x232设ⅹ=tanθ,则dⅹ=sec2θdθ.∴∫[x2/(1+x2)^(3/2)]dⅹ=∫(tan2θ/sec3θ)·sec2θdθ=∫(sin2θcosθ)dθ=∫sin2θd(sinθ)=(1/3)sin3θ+C=(1/3)·[x/√(1+x2)]3+C。2,x123带步骤解方程(x-
x21x232设ⅹ=tanθ,则dⅹ=sec2θdθ.∴∫[x2/(1+x2)^(3/2)]dⅹ=∫(tan2θ/sec3θ)·sec2θdθ=∫(sin2θcosθ)dθ=∫sin2θd(sinθ)=(1/3)sin3θ+C=(1/3)·[x/√(1+x2)]3+C。2,x123带步骤解方程(x-
x21x232设ⅹ=tanθ,则dⅹ=sec2θdθ.∴∫[x2/(1+x2)^(3/2)]dⅹ=∫(tan2θ/sec3θ)·sec2θdθ=∫(sin2θcosθ)dθ=∫sin2θd(sinθ)=(1/3)sin3θ+C=(1/3)·[x/√(1+x2)]3+C。2,x123带步骤解方程(x-
x21x232设ⅹ=tanθ,则dⅹ=sec2θdθ.∴∫[x2/(1+x2)^(3/2)]dⅹ=∫(tan2θ/sec3θ)·sec2θdθ=∫(sin2θcosθ)dθ=∫sin2θd(sinθ)=(1/3)sin3θ+C=(1/3)·[x/√(1+x2)]3+C。2,x123带步骤解方程(x-